- Mastering Visual Studio 2017
- Kunal Chowdhury
- 521字
- 2021-07-15 17:26:39
Getting to know about deconstruction syntax
Deconstruction is a syntax to split a value into multiple parts and store those parts individually into new variables. For example, tuples that return multiple values. Let us take the following method as an example, which returns a tuple of two string variables, Title and Author (see the New changes to tuples section):
public (string Title, string Author) GetBookDetails() { return (Title: "Mastering Visual Studio 2017",
Author: "Kunal Chowdhury"); }
Now, when you call the method GetBookDetails(), it will return a tuple. You can access its elements by calling the element name, as follows:
var bookDetails = GetBookDetails(); // returns Tuple Console.WriteLine("Title : " + bookDetails.Title); Console.WriteLine("Author : " + bookDetails.Author);
In a deconstructing declaration, you can split the tuple into parts and assign them directly into new variables. You can then access those variables individually, just like a local variable:
(string title, string author) = GetBookDetails(); Console.WriteLine("Title : " + title); Console.WriteLine("Author : " + author);
While deconstructing, you can also use var for the individual variables, instead of strong type names:
(var title, var author) = GetBookDetails(); Console.WriteLine("Title : " + title); Console.WriteLine("Author : " + author);
The preceding code can also be replaced by the following deconstruction syntax, by putting a single var outside the parentheses as an abbreviation:
var (title, author) = GetBookDetails(); Console.WriteLine("Title : " + title); Console.WriteLine("Author : " + author);
If you have existing variables with a deconstructing assignment, you can use the same variables to store the return values of a new call:
var (title, author) = GetBookDetails(); // deconstruct to existing variables (title, author) = GetAnotherBookDetails(); Console.WriteLine("Title : " + title); Console.WriteLine("Author : " + author);
Until now, we have learned how to write the syntax to deconstruct a tuple. In C# 7.0, it's not limited to tuples only. You can use deconstructing assignments for any type, as long as it has a Deconstruct method in the following form: public void Deconstruct (out T1 x1, ..., out Tn xn) { ... }.
For example, let us create a class named Book exposing the Deconstruct method with two out variables:
public class Book { public void Deconstruct (out string Title, out string Author) { Title = "Mastering Visual Studio 2017"; Author = "Kunal Chowdhury"; } }
As we didn't expose any properties to access the values of Title and Author from the Book class, we will not find them generally in the IntelliSense popup when trying to access an instance of the class. Refer to the following screenshot:

As we have declared the Deconstruct method in the class, you can directly deconstruct the instance into multiple variables to get the desired output of the return values:
var book = new Book(); var (title, author) = book; //var (title, author) = new Book(); Console.WriteLine("Title : " + title); Console.WriteLine("Author : " + author);
When you run the preceding code, you will get the following output in the console window:

- Deploying Node.js
- 深入理解Bootstrap
- 單片機C語言程序設計實訓100例:基于STC8051+Proteus仿真與實戰
- JMeter 性能測試實戰(第2版)
- 數據結構(Python語言描述)(第2版)
- 新手學Visual C# 2008程序設計
- VSTO開發入門教程
- Xamarin.Forms Projects
- Unity 2017 Mobile Game Development
- Orleans:構建高性能分布式Actor服務
- Django 3.0應用開發詳解
- Android初級應用開發
- Building Web and Mobile ArcGIS Server Applications with JavaScript(Second Edition)
- Learning Node.js for Mobile Application Development
- Implementing NetScaler VPX?(Second Edition)