In the previous examples, the type of the content that is hosted in a variable container was defined by the value that was assigned to a variable:
my $x; # Declaring a variable as a container. $x = 2; # Now it contains an integer. $x = 'Two'; # But now it keeps a string.
Perl 6 allows you to make the type of the variable container strict by specifying it together with a variable declaration:
my Int $x = 2;
Here, the $x variable will only be able to accept integers. An attempt to assign it to a string, for example, will result in the following error:
$x = 'Two'; # Type check failed in assignment to $x; # expected Int but got Str ("Two")
Similarly, Perl 6 allows elements of different types in the same array:
my @a = (1, 'two', 3.0);
Declaring an array with a type makes its element typed values. This means that you cannot assign a value of another type to it, as shown in the next example:
my Int @a; @a = 1, 2, 3; say @a; @a[2] = 'Two';
The last assignment causes the type check error:
Type check failed in assignment to @a; expected Int but got Str ("Two") in block <unit> at typed-arr.pl line 7
Typed variables can use any of the built-in types or user-defined classes. In the next section, we will talk about the data types available in Perl 6 by default. In Chapter 8, Object-Oriented Programming, you will learn how to create your own classes.